moles C2H5NH2=0.150mol C2H5NH3L 20.0 mL x 10-3 L1 mL

moles C2H5NH2 = 0.003 mol

moles HCl=0.0981mol HClL 5.0 mL x 10-3 L1 mL

moles HCl = 4.905×10‒4 mol

Step 2: build an ICF chart to identify the last amount of every species.

You are watching: What is the ph after the addition of 5.0 ml of hcl? for ethylamine, pkb= 3.25.

82% (72 ratings) Problem Details

A 20.0 mL sample of 0.150 M ethylamine is titrated through 0.0981 M HCl. What is the pH after the addition of 5.0 mL that HCl? for ethylamine, pKb= 3.25.

Learn this object by watchingWeak Base strong Acid Titrations ide Videos
All Chemistry Practice problems Weak Base solid Acid Titrations exercise Problems
Q.How do you calculation the pH in ~ the equivalence suggest for the titration that .190M methylamine through .190M HCl? The Kb the methylamine is 5.0 x 10-4.
Q.Consider the titration that 30.0 mL of 0.050 M NH3 with 0.025 M HCl. Calculation the pH after the complying with volumes of titrant have actually been added.20.0 mL
Q.A 25.0-mL sample of 0.125 M pyridine is titrated v 0.100 M HCl.Calculate the pH in ~ 20 mL of included acid.
Q.A 25.0-mL sample of 0.125 M pyridine is titrated v 0.100 M HCl.Calculate the pH at equivalence point.
See all difficulties in Weak Base strong Acid Titrations

What scientific concept do you require to know in bespeak to fix this problem?

Our tutors have actually indicated that to fix this trouble you will need to use the Weak Base solid Acid Titrations concept. You can view video clip lessons to learn Weak Base strong Acid Titrations. Or if girlfriend need an ext Weak Base strong Acid Titrations practice, friend can additionally practice Weak Base solid Acid Titrations practice problems.

What professor is this trouble relevant for?

Based on our data, us think this difficulty is relevant for Professor Zhang's class at USF.

subjects
schools
find
ACCOUNT
legit © 2021 Clutch Learning, Inc. Clutch prepare is not funded or endorsed by any kind of college or university.
×

OR
email